Rotor-Furl Coordinate System

[Mohamed.Fekry]

I have a question regarding the transformation matrix
- How can I derivative the rotational matrix from Nacelle / Yaw Coordinate System (d1,d2,d3) to Rotor-Furl Coordinate System (rf1,rf2,rf3) ? Where is the origin location of Rotor-Furl Coordinate System (rf1,rf2,rf3)?
Please provide me with the required papers to understand this part
Thanks

[Jason.Jonkman]

Dear Mohamed,

I can't seem to find the derivation of the transformation matrix between the nacelle and rotor-furl coordinate system published in any report. However, the transformation can be derived by multiplying several simpler 3x3 matrices together i.e.

{rf} = [TransMat] * {d}
with
[TransMat] = [RFrlSkew]^T * [RFrlTilt]^T * [q_RFrl] * [RFrlTilt] * [RFrlSkew]

where,
{} represents a 3x1 vector
[] represents a 3x3 matrix
^T represents a matrix transpose
[RFrlSkew] represents the transformation matrix associated with the single rotation RFrlSkew
[RFrlTilt] represents the transformation matrix associated with the single rotation RFirlTilt
[q_RFrl] represents the transformation matrix associated with the single rotation of RFrlDOF

The origin of the rotor-furl coordinate system is not defined nor used in FAST.

I hope that helps.

Best regards,

[Mohamed.Fekry]

Thank you for your explanation. However, I have a question
Why it is necessary to use Similarity Transformations and express the [q_RFrl] rotational matrix in Yaw frame?
It seems that the rotations [RFrlSkew] and [RFrlTilt] are made with respect to current frame concept (not fixed frame concept).

[Jason.Jonkman]

Dear Mohamed,

I'm not sure I understand your question, but [TransMat] in this case is defined such that {d} and {rf} coordinate systems are parallel {rf} = {d} when q_RFrl = 0, i.e. when [q_RFrl] = the 3x3 identity matrix.

Best regards,

[Mohamed.Fekry]

Thank you for kind consideration and clarification.
However, I mean that why the transformation between rotor furl frame {rf} and Yaw frame{d} was not like this
{rf} = [TransMat] * {d}
[TransMat] =[q_RFrl] * [RFrlTilt] * [RFrlSkew]

Also, I agree with you partially, {d} and {rf} coordinate systems are parallel {rf} = {d} only when q_RFrl = 0, RfrlSkew =0 and RfrlTilt=0

So, Why it is necessary to add( [RFrlSkew]^T * [RFrlTilt]^T ) to the [TransMat] ?

[Jason.Jonkman]

Dear Mohammed,

[RFrlSkew]^T * [RFrlTilt]^T are included in [TransMat] so that {rf} = {d} for any value of RFrlSkew and RFrlTIlt, as long as q_RFrl = 0.

Best regards,